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implement是什么意思

2022-11-11 11:31:57| 收藏本文下载本文作者：米三Chen

以下是小编帮大家整理的implement是什么意思（共含8篇），仅供参考，希望能够帮助到大家。同时，但愿您也能像本文投稿人“米三Chen”一样，积极向本站投稿分享好文章。

implement是什么意思

篇1：implement是什么意思

Implement the business logic.

实现业务逻辑。

Implement conversion scripts.

执行转换脚本。

Implement an endpoint interface.

实现端点接口。

篇2：A scheme to implement the Deutsch-Jo

A scheme to implement the Deutsch-Josza algorithm on a superconducting charge-qubit quantum computer

We have studied the implementation of the Deutsch-Josza quantum algorithm in a superconducting charge-qubit quantum computer. Different from previous studies, we have used the inductance coupled system of You et al. The detailed pulse sequences have been designed for the four possible functions in a 2-qubit system. The result is generalized to an arbitrary n-qubit system. This scheme will be useful for practical implementation of the algorithm.

作者：HUO Wenyi LONG Guilu 作者单位：HUO Wenyi(Key Laboratory for Quantum Information and Measurements, and Department of Physics, Tsinghua University, Beijing 100084,China)

LONG Guilu(Key Laboratory for Quantum Information and Measurements, and Department of Physics, Tsinghua University, Beijing 100084,China;Key Laboratory for Atomic and Molecular NanoSciences, Tsinghua University, Beijing 100084, China)

刊名：自然科学进展（英文版） SCI英文刊名：PROGRESS IN NATURAL SCIENCE 年，卷(期)： 16(6) 分类号：N1 关键词：superconducting quantum computer Deutsch-Josza algorithm

篇3：leetcode笔记：Implement strStr

一.题目描述

Implement strStr.

Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack.

二.题目分析

实现strstr()函数，返回needle(关键字)在haystack(字符串)中第一次出现的位置，如果needle不在haystack中，则返回-1。由于使用暴力方法的时间复杂度为O(mn)会超时，可使用著名的KMP算法解决。该是由Knuth，Morris，Pratt共同提出的字符串匹配算法，其对于任何字符串和目标字符串，都可以在线性时间内完成匹配查找，是一个非常优秀的字符串匹配算法。

三.示例代码

KMP算法：

class Solution {public: void getNext(vector&next, string &needle) { int i = 0, j = -1; next[i] = j; while (i != needle.length()) {while (j != -1 && needle[i] != needle[j]) j = next[j];next[++i] = ++j; } } int strStr(string haystack, string needle) { if (haystack.empty()) return needle.empty() ? 0 : -1; if (needle.empty()) return 0; vectornext(needle.length() + 1); getNext(next, needle); int i = 0, j = 0; while (i != haystack.length()) {while (j != -1 && haystack[i] != needle[j]) j = next[j];++i; ++j;if (j == needle.length()) return i - j; } return -1; }};

四.小结

对于这题，还有其他一些有名的算法，如Rabin-Karp和Boyer-Moore算法，

篇4：LeetCode Implement Trie (Prefix Tree)

题目描述：

Implement Trie (Prefix Tree)

Implement a trie with insert, search, and startsWith methods.

Note:

You may assume that all inputs are consist of lowercase letters a-z.

思路：

1.由于题目可以假设所有input均为小写字母，因此每个节点存1个字符，

2.root的val保持空

3.创建树时，不断拿去当前word[i]的字符,i∈[0,n)，如果word[i]在当前node的children中找不到，就添加到children中。同时把最后一个节点标记（hasWord）为是否为单词的末尾。

4.搜索时，每次拿word[i]的字符，逐层判断即可。如果是Search，判断最后到达的字符是否标记为hasWord；如果仅仅搜索prefix，只需判断i是否到word结尾即可。

实现代码：

public class TrieNode { // Initialize your data structure here. public TrieNode() { children = new List(); hasWord = false; } public TrieNode(char v){ val = v; children = new List(); hasWord = false; } public IListchildren; public char val; public bool hasWord ;}public class Trie { public TrieNode root; public Trie() { root = new TrieNode(); } // Inserts a word into the trie. public void Insert(String word) { if(string.IsNullOrEmpty(word)){ return; } var n = root; var index = 0; // try find while(n.children.Count >0 && index < word.Length){ var first = n.children.FirstOrDefault(x=>x.val == word[index]); if(first != null){ n = first; index++; } else{ break; } } if(index < word.Length){ // if not exist , create new node for(var i = index; i < word.Length; i++){ var child = new TrieNode(word[i]); n.children.Add(child); n = child; } } n.hasWord = true;} // Returns if the word is in the trie. public bool Search(string word) { TrieNode n = null; var index = TryFindNode(word, out n); return index == word.Length && n.hasWord; } // Returns if there is any word in the trie // that starts with the given prefix. public bool StartsWith(string word) { TrieNode n = null; var index = TryFindNode(word, out n); return index == word.Length; } private int TryFindNode(string word, out TrieNode node){ var n = root; var index = 0; while(n.children.Count >0 && index < word.Length){ var first = n.children.FirstOrDefault(x =>x.val == word[index]); if(first != null){ n = first; index++; } else{ break; } } node = n;; return index; }}