以下是小编为大家准备的KPMG英文式笔试题（共含8篇），希望对大家有帮助。同时，但愿您也能像本文投稿人“骁炎非”一样，积极向本站投稿分享好文章。
KPMG英文式笔试题
KPMG英文式笔试题，应届毕业生求职网总结如下，供参考：
“The big economic difference between nuclear and fossil-fuelled power stations is that nuclear reactors are more expensive to build and decommission, but cheaper to sun. So disputes over the relative efficiency of the two systems revolve not just around prices of coal and uranium today and tomorrow, but also around the way in which future income should be compared with current income.”
1. The main difference between nuclear and fossil-fuelled power stations is an economic one.
TRUE
UNTRUE
CANNOT SAY
2. The price of coal is not relevant to discussions about the relative efficiency of nuclear reactors.
TRUE
UNTRUE
CANNOT SAY
3. If nuclear reactors were cheaper to build and decommission than fossil-fuelled power stations, they would definitely have the economic advantage.
TRUE
UNTRUE
CANNOT SAY
“At any given moment we are being bombarded by physical and psychological stimuli competing for our attention. Although our eyes are capable of handling more than 5 million bits of data per second, our brain are capable of interpreting only about 500 bits per second. With similar disparities between each of the other senses and the brain, it is easy to see that we must select the visual, auditory, or tactile stimuli that we wish to compute at any specific time.”
4.Physical stimuli usually win in the competition for our attention.
TRUE
UNTRUE
CANNOT SAY
5. The capacity of the human brain is sufficient to interpret nearly all the stimuli the senses can register under optimum conditions.
TRUE
UNTRUE
CANNOT SAY
6. Eyes are able to cope with a greater input of information than ears.
TRUE
UNTRUE
CANNOT SAY
“The big economic difference between nuclear and fossil-fuelled power sta tions is that nuclear reactors are more expensive to build and decommission, but cheaper to sun. So disputes over the relative efficiency of the two systems revolve not just around prices of coal and uranium today and tomorrow, but also around the way in which future income should be compared with current income.”
1. The main difference between nuclear and fossil-fuelled power stations is an economic one.
TRUE
UNTRUE
CANNOT SAY
2. The price of coal is not relevant to discussions about the relative efficiency of nuclear reactors.
TRUE
UNTRUE
CANNOT SAY
3. If nuclear reactors were cheaper to build and decommission than fossilfuelled power stations, they would definitely have the economic advantage. my.chinahrlab.com
TRUE
UNTRUE
CANNOT SAY
“At any given moment we are being bombarded by physical and psychologicalstimuli competing for our attention. Although our eyes are capable of handling more than 5 million bits of data per second, our brain are capable of interpreting only about 500 bits per second. With similar disparities between each of the other senses and the brain, it is easy to see that we must select the visual, auditory, or tactile stimuli that we wish to compute at any specific tim e.”
4. Physical stimuli usually win in the competition for our attention.
TRUE
UNTRUE
CANNOT SAY
5. The capacity of the human brain is sufficient to interpret nearly all the stimuli the senses can register under optimum conditions.
TRUE
UNTRUE
CANNOT SAY
6. Eyes are able to cope with a greater input of information than ears.
TRUE
UNTRUE
CANNOT SAY
VERBAL ANSWER：
（1）C CANNOT SAY
（2）B UNTRUE
（3）A TRUE
（4）C CANNOT SAY
（5）B UNTRUE
，
笔试内容就是经典24题+36个阅读题。考试24题用中文，解题思路与经典24题一致，36阅读可能有经典题原题。所以我认为kpmg的`笔试就是比人品和运气，我24题答得不错，但36题仅仅遇到了一个半阅读就和6个题是一致的，我的同学则是三个半阅读，14个题，据说能超一半就可以过去，我距离这个还远得很。这实在是不能令人心服口服啊!
英文笔试题
1. tranlation (mandatory)
cdma venders have worked hard to give cdma roaming capabilities via the development of ruim-essentially, a sim card for cdma handsets currently being deployed in china for new cdma operator china unicom. korean cellco ktf demonstrated earlier this year the ability to roam between gsm and cdma using such cards.however,only the card containing the user’s service data can roam-not the cdma handset or the user’s number (except via call forwarding).
2. programming (mandatory)
linked list
a. implement a linked list for integers,which supports the insertafter (insert a node after a specified node) and removeafter (remove the node after a specified node)methods;
b. implement a method to sort the linked list to descending order.
3. debugging (mandatory)
a. for each of the following recursive methods,enter y in the answer box if the method terminaters (assume i=5), otherwise enter n.static int f(int i){
return f(i-1)*f(i-1);
}
ansewr:
static int f(int i){
if(i==0){return 1;}
else {return f(i-1)*f(i-1);}
}
ansewr:
英文阅读笔试题
The Donkey and the Statue
A donkey was once chosen to carry a holy statue through the town.Crowds of peoplle came from all over the countryside to see the procession.They lined both sides of thee street,pushing and jostling to get nearer to the front.As the donkey went pass all the people bowen down to pray to the statue.some of them reached out their hands to touch it;others knelt down on their knees bu the roadd in front of it.The donkey began to feel he was avery impoutant animal.
'Fancy all these people showing me so much respect.'he thought,'I never knew I was so powerful.To think that all thes time I have been doing everything my master toldd me.' He decided to try out his power.
'I really don't feel like walking any further,'he said to himself.'I'lljust stannd here for a while and let the people admire me.'And he refused to take another step.The wack1A sharp blow fell on his back.
'Get along with you,'hissed his master angrily.'What do you mean by holding up the procession like this/'
'All in good time.'replied the donkey grandly.'I am just giving these good people a chance to look at me.'His master began to laugh loudly.
QUESTIONS
1.Summarize the story within 50 words by using at least 8 key words from the passsage.
2.Why did this master laugh/
3.What do you learn from this story/And how to utilize in your life/
It consists of number series.In some institutes alphabetical series is given instead of number series.Iam having number series so iam sending that.Please go through tha alphabetical tests also.
1. 30,28,25,20,34,28,?
a:21
2 4,8,16,32,64,128,?
a:256
3. 8,16,24,32,40,48,?
a:56
4. 13,11,14,12,15,13,?
a:16
5. 6,18,36,108,216,648,?
a:1296
6 4,4,8,8,16,16,?
a:32
7. 2,6,18,54,162,486,?
a:1458
8 4,20,35,49,62,74,?
a:85
9. 10,18,15,23,20,28,?
a:25
10 . 4,10,8,14,12,18,?
a:16
11 .10,15,12,17,14,10,?
a:16
part 2
consists of non-verbal reasoning (figures). So it is impossible for me to send those.(25 questions)
part 3 (quantitative)
机械类笔试题（英文）
德尔福集团是全球最大的汽车系统和零部件生产制造商,
1,Briefly describe what is blanking(cutting),forming,coining and embossing in stamping process.
2,What is metal clading?
3,What is the purpose of adding glass fiber to thermoplastic material?
4,In contrast with metal and thermoplastic material,which has a higher coefficient of thermal expansion(CTE).
5,The most suitable material for a integral hinge design(typical plastic thickness=0.25 to 0.5mm at hinge)
6,Can a bending load makes both compressive and tensile stress in a member?
7,What is the design criteria used in plastics catch/snap?
8,What is FEA?
9,Why is natural frequency important in vibration analysis?
10,What is the deflection equation of a cantilever beam fixed at one edge?
技工英文笔试题
选择题
1:Which property of the output capacitor is the primary cause of Low Drop Out(LDO) regulator loop instability?
A.Equivalent series resistance(ESR)
B.Effective series inductance(ESL)
C.Capacitance value
D.Dielectric material
2:A律13折线通常采用的量化级数为，
A.16
B.256
C.128
D.2048
3:伪指令DA1 DB 04H DUP(3 DUP(2)， 2 DUP(3))在数据区中能构成0203H操作数共有
A.07个
B.04个
C.03个
D.02个
4:异步复接二次群帧周期是。
A.100.38μs
B.125μs
C.250μs
D.500μs
5:假设存储器中从7462H单元开始的四个相邻字节单元中的内容依次是32H，46H，52H，OFEH，则存放字数据OFE52H的字地址是
A.7462H
B.7463H
C.7464H
D.7465H
6:在指令的操作数字段中，允许出现表达式，若BUF1与BUF2均为变量名，下面指令中正确的是
A.MOV DX，BUF1*BUF2
B.MOV DX，BUF1/BUF2
C.MOV DX，(BUF1*BUF2)-BUF1
D.MOV DX，BUF2-BUF1
7:下列指令中操作数在代码段中的是
A.MOV AL，42H
B.ADD AL，BL
C.SUB [BX]，DI
D.1NC [DI]
8:无条件转移指令JMP实现段间间接转移，转移的'目标地址在
A.某个字存储单元中
B.某个双字存储单元中
C.某个16位通用寄存器中
D.两个16位通用寄存器中
9:DB1 DB 8 DUP2 DUP3，3 DUP2
┇
MOV AX，WORD PTR DB1 [04H]
上面指令执行后，AX的内容是
A.0302H
B.0203H
C.0202H
D.0303H
10:下列指令执行后既能使AX=0同时又使CF=0,OF=0的是
A.XOR AX，AX
B.AND AX，AX
C.OR AX，AX
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